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令u(x)=Σ(n=1,∞)nx^(n-1)∫(0,x)u(t)dt=Σ(n=1,∞)x^n=1/(1-x)-1=x/(1-x)u(x)=[x/(1-x)]'=1/(1-x)+x/(1-x)²=1/(1-x)²所以所求的和函数为1/(1-x)²令x=1/2,则Σ(n=1,∞)n/[2^(n-1)]=1/(1/2)²=4...